Solve for x
x=-24
x=18
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x^{2}+6x-432=0
Subtract 432 from both sides.
a+b=6 ab=-432
To solve the equation, factor x^{2}+6x-432 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.
-1,432 -2,216 -3,144 -4,108 -6,72 -8,54 -9,48 -12,36 -16,27 -18,24
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -432.
-1+432=431 -2+216=214 -3+144=141 -4+108=104 -6+72=66 -8+54=46 -9+48=39 -12+36=24 -16+27=11 -18+24=6
Calculate the sum for each pair.
a=-18 b=24
The solution is the pair that gives sum 6.
\left(x-18\right)\left(x+24\right)
Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.
x=18 x=-24
To find equation solutions, solve x-18=0 and x+24=0.
x^{2}+6x-432=0
Subtract 432 from both sides.
a+b=6 ab=1\left(-432\right)=-432
To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-432. To find a and b, set up a system to be solved.
-1,432 -2,216 -3,144 -4,108 -6,72 -8,54 -9,48 -12,36 -16,27 -18,24
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -432.
-1+432=431 -2+216=214 -3+144=141 -4+108=104 -6+72=66 -8+54=46 -9+48=39 -12+36=24 -16+27=11 -18+24=6
Calculate the sum for each pair.
a=-18 b=24
The solution is the pair that gives sum 6.
\left(x^{2}-18x\right)+\left(24x-432\right)
Rewrite x^{2}+6x-432 as \left(x^{2}-18x\right)+\left(24x-432\right).
x\left(x-18\right)+24\left(x-18\right)
Factor out x in the first and 24 in the second group.
\left(x-18\right)\left(x+24\right)
Factor out common term x-18 by using distributive property.
x=18 x=-24
To find equation solutions, solve x-18=0 and x+24=0.
x^{2}+6x=432
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x^{2}+6x-432=432-432
Subtract 432 from both sides of the equation.
x^{2}+6x-432=0
Subtracting 432 from itself leaves 0.
x=\frac{-6±\sqrt{6^{2}-4\left(-432\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 6 for b, and -432 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-6±\sqrt{36-4\left(-432\right)}}{2}
Square 6.
x=\frac{-6±\sqrt{36+1728}}{2}
Multiply -4 times -432.
x=\frac{-6±\sqrt{1764}}{2}
Add 36 to 1728.
x=\frac{-6±42}{2}
Take the square root of 1764.
x=\frac{36}{2}
Now solve the equation x=\frac{-6±42}{2} when ± is plus. Add -6 to 42.
x=18
Divide 36 by 2.
x=-\frac{48}{2}
Now solve the equation x=\frac{-6±42}{2} when ± is minus. Subtract 42 from -6.
x=-24
Divide -48 by 2.
x=18 x=-24
The equation is now solved.
x^{2}+6x=432
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+6x+3^{2}=432+3^{2}
Divide 6, the coefficient of the x term, by 2 to get 3. Then add the square of 3 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+6x+9=432+9
Square 3.
x^{2}+6x+9=441
Add 432 to 9.
\left(x+3\right)^{2}=441
Factor x^{2}+6x+9. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+3\right)^{2}}=\sqrt{441}
Take the square root of both sides of the equation.
x+3=21 x+3=-21
Simplify.
x=18 x=-24
Subtract 3 from both sides of the equation.
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Simultaneous equation
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Differentiation
\frac { d } { d x } \frac { ( 3 x ^ { 2 } - 2 ) } { ( x - 5 ) }
Integration
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Limits
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