Solve x^2+5x-4=x^2+x-12

$${ x }^{ 2 } +5x-4= { x }^{ 2 } +x-12$$

Solve for x

$$x=-2$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$x^{2}+5x-4-x^{2}=x-12$$

Combine x^{2} and -x^{2} to get 0.

$$5x-4=x-12$$

Subtract x from both sides.

$$5x-4-x=-12$$

Combine 5x and -x to get 4x.

$$4x-4=-12$$

Add 4 to both sides.

$$4x=-12+4$$

Add -12 and 4 to get -8.

$$4x=-8$$

Divide both sides by 4.

$$x=\frac{-8}{4}$$

Divide -8 by 4 to get -2.

$$x=-2$$