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a+b=5 ab=1\left(-14\right)=-14
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-14. To find a and b, set up a system to be solved.
-1,14 -2,7
Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -14.
-1+14=13 -2+7=5
Calculate the sum for each pair.
a=-2 b=7
The solution is the pair that gives sum 5.
\left(x^{2}-2x\right)+\left(7x-14\right)
Rewrite x^{2}+5x-14 as \left(x^{2}-2x\right)+\left(7x-14\right).
x\left(x-2\right)+7\left(x-2\right)
Factor out x in the first and 7 in the second group.
\left(x-2\right)\left(x+7\right)
Factor out common term x-2 by using distributive property.
x^{2}+5x-14=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-5±\sqrt{5^{2}-4\left(-14\right)}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-5±\sqrt{25-4\left(-14\right)}}{2}
Square 5.
x=\frac{-5±\sqrt{25+56}}{2}
Multiply -4 times -14.
x=\frac{-5±\sqrt{81}}{2}
Add 25 to 56.
x=\frac{-5±9}{2}
Take the square root of 81.
x=\frac{4}{2}
Now solve the equation x=\frac{-5±9}{2} when ± is plus. Add -5 to 9.
x=2
Divide 4 by 2.
x=-\frac{14}{2}
Now solve the equation x=\frac{-5±9}{2} when ± is minus. Subtract 9 from -5.
x=-7
Divide -14 by 2.
x^{2}+5x-14=\left(x-2\right)\left(x-\left(-7\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 2 for x_{1} and -7 for x_{2}.
x^{2}+5x-14=\left(x-2\right)\left(x+7\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.