Solve x^2+50x+600=5600

$${ x }^{ 2 } +50x+600=5600$$

Solve for x

$$x=-100$$

$$x=50$$

Steps Using Factoring

Subtract 5600 from both sides.

$$x^{2}+50x+600-5600=0$$

Subtract 5600 from 600 to get -5000.

$$x^{2}+50x-5000=0$$

To solve the equation, factor x^{2}+50x-5000 using formula x^{2}+\left(a+b\right)x+ab=\left(x+a\right)\left(x+b\right). To find a and b, set up a system to be solved.

$$a+b=50 ab=-5000$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -5000.

$$-1,5000 -2,2500 -4,1250 -5,1000 -8,625 -10,500 -20,250 -25,200 -40,125 -50,100$$

Calculate the sum for each pair.

$$-1+5000=4999 -2+2500=2498 -4+1250=1246 -5+1000=995 -8+625=617 -10+500=490 -20+250=230 -25+200=175 -40+125=85 -50+100=50$$

The solution is the pair that gives sum 50.

$$a=-50 b=100$$

Rewrite factored expression \left(x+a\right)\left(x+b\right) using the obtained values.

$$\left(x-50\right)\left(x+100\right)$$

To find equation solutions, solve x-50=0 and x+100=0.

$$x=50 x=-100$$

Steps Using Factoring By Grouping

Subtract 5600 from both sides.

$$x^{2}+50x+600-5600=0$$

Subtract 5600 from 600 to get -5000.

$$x^{2}+50x-5000=0$$

To solve the equation, factor the left hand side by grouping. First, left hand side needs to be rewritten as x^{2}+ax+bx-5000. To find a and b, set up a system to be solved.

$$a+b=50 ab=1\left(-5000\right)=-5000$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -5000.

$$-1,5000 -2,2500 -4,1250 -5,1000 -8,625 -10,500 -20,250 -25,200 -40,125 -50,100$$

Calculate the sum for each pair.

$$-1+5000=4999 -2+2500=2498 -4+1250=1246 -5+1000=995 -8+625=617 -10+500=490 -20+250=230 -25+200=175 -40+125=85 -50+100=50$$

The solution is the pair that gives sum 50.

$$a=-50 b=100$$

Rewrite x^{2}+50x-5000 as \left(x^{2}-50x\right)+\left(100x-5000\right).

$$\left(x^{2}-50x\right)+\left(100x-5000\right)$$

Factor out x in the first and 100 in the second group.

$$x\left(x-50\right)+100\left(x-50\right)$$

Factor out common term x-50 by using distributive property.

$$\left(x-50\right)\left(x+100\right)$$

To find equation solutions, solve x-50=0 and x+100=0.

$$x=50 x=-100$$

Steps Using the Quadratic Formula

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x^{2}+50x+600=5600$$

Subtract 5600 from both sides of the equation.

$$x^{2}+50x+600-5600=5600-5600$$

Subtracting 5600 from itself leaves 0.

$$x^{2}+50x+600-5600=0$$

Subtract 5600 from 600.

$$x^{2}+50x-5000=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 50 for b, and -5000 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{-50±\sqrt{50^{2}-4\left(-5000\right)}}{2}$$

Square 50.

$$x=\frac{-50±\sqrt{2500-4\left(-5000\right)}}{2}$$

Multiply -4 times -5000.

$$x=\frac{-50±\sqrt{2500+20000}}{2}$$

Add 2500 to 20000.

$$x=\frac{-50±\sqrt{22500}}{2}$$

Take the square root of 22500.

$$x=\frac{-50±150}{2}$$

Now solve the equation x=\frac{-50±150}{2} when ± is plus. Add -50 to 150.

$$x=\frac{100}{2}$$

Divide 100 by 2.

$$x=50$$

Now solve the equation x=\frac{-50±150}{2} when ± is minus. Subtract 150 from -50.

$$x=-\frac{200}{2}$$

Divide -200 by 2.

$$x=-100$$

The equation is now solved.

$$x=50 x=-100$$

Steps for Completing the Square

Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.

$$x^{2}+50x+600=5600$$

Subtract 600 from both sides of the equation.

$$x^{2}+50x+600-600=5600-600$$

Subtracting 600 from itself leaves 0.

$$x^{2}+50x=5600-600$$

Subtract 600 from 5600.

$$x^{2}+50x=5000$$

Divide 50, the coefficient of the x term, by 2 to get 25. Then add the square of 25 to both sides of the equation. This step makes the left hand side of the equation a perfect square.

$$x^{2}+50x+25^{2}=5000+25^{2}$$

Square 25.

$$x^{2}+50x+625=5000+625$$

Add 5000 to 625.

$$x^{2}+50x+625=5625$$

Factor x^{2}+50x+625. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.

$$\left(x+25\right)^{2}=5625$$

Take the square root of both sides of the equation.

$$\sqrt{\left(x+25\right)^{2}}=\sqrt{5625}$$

Simplify.

$$x+25=75 x+25=-75$$

Subtract 25 from both sides of the equation.

$$x=50 x=-100$$