Solve x^2+5-(x-1)*(x+3)=4x-7

$${ x }^{ 2 } +5-(x-1) \times (x+3)=4x-7$$

Solve for x

$$x = \frac{5}{2} = 2\frac{1}{2} = 2.5$$

Steps for Solving Linear Equation

Use the distributive property to multiply x-1 by x+3 and combine like terms.

$$x^{2}+5-\left(x^{2}+2x-3\right)=4x-7$$

To find the opposite of x^{2}+2x-3, find the opposite of each term.

$$x^{2}+5-x^{2}-2x+3=4x-7$$

Combine x^{2} and -x^{2} to get 0.

$$5-2x+3=4x-7$$

Add 5 and 3 to get 8.

$$8-2x=4x-7$$

Subtract 4x from both sides.

$$8-2x-4x=-7$$

Combine -2x and -4x to get -6x.

$$8-6x=-7$$

Subtract 8 from both sides.

$$-6x=-7-8$$

Subtract 8 from -7 to get -15.

$$-6x=-15$$

Divide both sides by -6.

$$x=\frac{-15}{-6}$$

Reduce the fraction \frac{-15}{-6} to lowest terms by extracting and canceling out -3.

$$x=\frac{5}{2}$$