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2x^{2}+10=5^{2}
Multiply both sides of the equation by 2.
2x^{2}+10=25
Calculate 5 to the power of 2 and get 25.
2x^{2}=25-10
Subtract 10 from both sides.
2x^{2}=15
Subtract 10 from 25 to get 15.
x^{2}=\frac{15}{2}
Divide both sides by 2.
x=\frac{\sqrt{30}}{2} x=-\frac{\sqrt{30}}{2}
Take the square root of both sides of the equation.
2x^{2}+10=5^{2}
Multiply both sides of the equation by 2.
2x^{2}+10=25
Calculate 5 to the power of 2 and get 25.
2x^{2}+10-25=0
Subtract 25 from both sides.
2x^{2}-15=0
Subtract 25 from 10 to get -15.
x=\frac{0±\sqrt{0^{2}-4\times 2\left(-15\right)}}{2\times 2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 2 for a, 0 for b, and -15 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{0±\sqrt{-4\times 2\left(-15\right)}}{2\times 2}
Square 0.
x=\frac{0±\sqrt{-8\left(-15\right)}}{2\times 2}
Multiply -4 times 2.
x=\frac{0±\sqrt{120}}{2\times 2}
Multiply -8 times -15.
x=\frac{0±2\sqrt{30}}{2\times 2}
Take the square root of 120.
x=\frac{0±2\sqrt{30}}{4}
Multiply 2 times 2.
x=\frac{\sqrt{30}}{2}
Now solve the equation x=\frac{0±2\sqrt{30}}{4} when ± is plus.
x=-\frac{\sqrt{30}}{2}
Now solve the equation x=\frac{0±2\sqrt{30}}{4} when ± is minus.
x=\frac{\sqrt{30}}{2} x=-\frac{\sqrt{30}}{2}
The equation is now solved.