Solve x^2+5+4=0

$${ x }^{ 2 } +5+4 = 0$$

Solve for x (complex solution)

$$x=-3i$$

$$x=3i$$

Steps by Finding Square Root

Add 5 and 4 to get 9.

$$x^{2}+9=0$$

Subtract 9 from both sides. Anything subtracted from zero gives its negation.

$$x^{2}=-9$$

The equation is now solved.

$$x=3i x=-3i$$

Steps Using the Quadratic Formula

Add 5 and 4 to get 9.

$$x^{2}+9=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 9 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\times 9}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\times 9}}{2}$$

Multiply -4 times 9.

$$x=\frac{0±\sqrt{-36}}{2}$$

Take the square root of -36.

$$x=\frac{0±6i}{2}$$

Now solve the equation x=\frac{0±6i}{2} when ± is plus.

$$x=3i$$

Now solve the equation x=\frac{0±6i}{2} when ± is minus.

$$x=-3i$$

The equation is now solved.

$$x=3i x=-3i$$