Solve x^2+2y-3z=26

$${ x }^{ 2 } +2y-3z=26$$

Solve for y

$$y=-\frac{x^{2}}{2}+\frac{3z}{2}+13$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$2y-3z=26-x^{2}$$

Add 3z to both sides.

$$2y=26-x^{2}+3z$$

The equation is in standard form.

$$2y=26+3z-x^{2}$$

Divide both sides by 2.

$$\frac{2y}{2}=\frac{26+3z-x^{2}}{2}$$

Dividing by 2 undoes the multiplication by 2.

$$y=\frac{26+3z-x^{2}}{2}$$

Divide 26-x^{2}+3z by 2.

$$y=-\frac{x^{2}}{2}+\frac{3z}{2}+13$$

Solve for x (complex solution)

$$x=-\sqrt{26+3z-2y}$$

$$x=\sqrt{26+3z-2y}$$

Solve for x

$$x=\sqrt{26+3z-2y}$$

$$x=-\sqrt{26+3z-2y}\text{, }y\leq \frac{3z}{2}+13$$