Solve x^2+2x-35

$${ x }^{ 2 } +2x-35$$

Factor

$$\left(x-5\right)\left(x+7\right)$$

Solution Steps

Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx-35. To find a and b, set up a system to be solved.

$$a+b=2 ab=1\left(-35\right)=-35$$

Since ab is negative, a and b have the opposite signs. Since a+b is positive, the positive number has greater absolute value than the negative. List all such integer pairs that give product -35.

$$-1,35 -5,7$$

Calculate the sum for each pair.

$$-1+35=34 -5+7=2$$

The solution is the pair that gives sum 2.

$$a=-5 b=7$$

Rewrite x^{2}+2x-35 as \left(x^{2}-5x\right)+\left(7x-35\right).

$$\left(x^{2}-5x\right)+\left(7x-35\right)$$

Factor out x in the first and 7 in the second group.

$$x\left(x-5\right)+7\left(x-5\right)$$

Factor out common term x-5 by using distributive property.

$$\left(x-5\right)\left(x+7\right)$$

Steps Using the Quadratic Formula

Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.

$$x^{2}+2x-35=0$$

All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.

$$x=\frac{-2±\sqrt{2^{2}-4\left(-35\right)}}{2}$$

Square 2.

$$x=\frac{-2±\sqrt{4-4\left(-35\right)}}{2}$$

Multiply -4 times -35.

$$x=\frac{-2±\sqrt{4+140}}{2}$$

Add 4 to 140.

$$x=\frac{-2±\sqrt{144}}{2}$$

Take the square root of 144.

$$x=\frac{-2±12}{2}$$

Now solve the equation x=\frac{-2±12}{2} when ± is plus. Add -2 to 12.

$$x=\frac{10}{2}$$

Divide 10 by 2.

$$x=5$$

Now solve the equation x=\frac{-2±12}{2} when ± is minus. Subtract 12 from -2.

$$x=-\frac{14}{2}$$

Divide -14 by 2.

$$x=-7$$

Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute 5 for x_{1} and -7 for x_{2}.

$$x^{2}+2x-35=\left(x-5\right)\left(x-\left(-7\right)\right)$$

Simplify all the expressions of the form p-\left(-q\right) to p+q.

$$x^{2}+2x-35=\left(x-5\right)\left(x+7\right)$$

Evaluate

$$\left(x-5\right)\left(x+7\right)$$