Solve x^2+2x+4y-10=0

$${ x }^{ 2 } +2x+4y-10=0$$

Solve for y

$$y=-\frac{x^{2}}{4}-\frac{x}{2}+\frac{5}{2}$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides. Anything subtracted from zero gives its negation.

$$2x+4y-10=-x^{2}$$

Subtract 2x from both sides.

$$4y-10=-x^{2}-2x$$

Add 10 to both sides.

$$4y=-x^{2}-2x+10$$

The equation is in standard form.

$$4y=10-2x-x^{2}$$

Divide both sides by 4.

$$\frac{4y}{4}=\frac{10-2x-x^{2}}{4}$$

Dividing by 4 undoes the multiplication by 4.

$$y=\frac{10-2x-x^{2}}{4}$$

Divide -x^{2}-2x+10 by 4.

$$y=-\frac{x^{2}}{4}-\frac{x}{2}+\frac{5}{2}$$

Solve for x (complex solution)

$$x=\sqrt{11-4y}-1$$

$$x=-\sqrt{11-4y}-1$$

Solve for x

$$x=\sqrt{11-4y}-1$$

$$x=-\sqrt{11-4y}-1\text{, }y\leq \frac{11}{4}$$