Solve x^2+25=left(x+1right)^2

$${ x }^{ 2 } +25 = { \left(x+1 \right) }^{ 2 }$$

Solve for x

$$x=12$$

Steps for Solving Linear Equation

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+1\right)^{2}.

$$x^{2}+25=x^{2}+2x+1$$

Subtract x^{2} from both sides.

$$x^{2}+25-x^{2}=2x+1$$

Combine x^{2} and -x^{2} to get 0.

$$25=2x+1$$

Swap sides so that all variable terms are on the left hand side.

$$2x+1=25$$

Subtract 1 from both sides.

$$2x=25-1$$

Subtract 1 from 25 to get 24.

$$2x=24$$

Divide both sides by 2.

$$x=\frac{24}{2}$$

Divide 24 by 2 to get 12.

$$x=12$$