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a+b=24 ab=1\times 119=119
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+119. To find a and b, set up a system to be solved.
1,119 7,17
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 119.
1+119=120 7+17=24
Calculate the sum for each pair.
a=7 b=17
The solution is the pair that gives sum 24.
\left(x^{2}+7x\right)+\left(17x+119\right)
Rewrite x^{2}+24x+119 as \left(x^{2}+7x\right)+\left(17x+119\right).
x\left(x+7\right)+17\left(x+7\right)
Factor out x in the first and 17 in the second group.
\left(x+7\right)\left(x+17\right)
Factor out common term x+7 by using distributive property.
x^{2}+24x+119=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-24±\sqrt{24^{2}-4\times 119}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-24±\sqrt{576-4\times 119}}{2}
Square 24.
x=\frac{-24±\sqrt{576-476}}{2}
Multiply -4 times 119.
x=\frac{-24±\sqrt{100}}{2}
Add 576 to -476.
x=\frac{-24±10}{2}
Take the square root of 100.
x=-\frac{14}{2}
Now solve the equation x=\frac{-24±10}{2} when ± is plus. Add -24 to 10.
x=-7
Divide -14 by 2.
x=-\frac{34}{2}
Now solve the equation x=\frac{-24±10}{2} when ± is minus. Subtract 10 from -24.
x=-17
Divide -34 by 2.
x^{2}+24x+119=\left(x-\left(-7\right)\right)\left(x-\left(-17\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -7 for x_{1} and -17 for x_{2}.
x^{2}+24x+119=\left(x+7\right)\left(x+17\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.