Solve x^2+20=50

$${ x }^{ 2 } +20=50$$

Solve for x

$$x=\sqrt{30}\approx 5.477225575$$

$$x=-\sqrt{30}\approx -5.477225575$$

Steps by Finding Square Root

Subtract 20 from both sides.

$$x^{2}=50-20$$

Subtract 20 from 50 to get 30.

$$x^{2}=30$$

Take the square root of both sides of the equation.

$$x=\sqrt{30} x=-\sqrt{30}$$

Steps Using the Quadratic Formula

Subtract 50 from both sides.

$$x^{2}+20-50=0$$

Subtract 50 from 20 to get -30.

$$x^{2}-30=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -30 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}-4\left(-30\right)}}{2}$$

Square 0.

$$x=\frac{0±\sqrt{-4\left(-30\right)}}{2}$$

Multiply -4 times -30.

$$x=\frac{0±\sqrt{120}}{2}$$

Take the square root of 120.

$$x=\frac{0±2\sqrt{30}}{2}$$

Now solve the equation x=\frac{0±2\sqrt{30}}{2} when ± is plus.

$$x=\sqrt{30}$$

Now solve the equation x=\frac{0±2\sqrt{30}}{2} when ± is minus.

$$x=-\sqrt{30}$$

The equation is now solved.

$$x=\sqrt{30} x=-\sqrt{30}$$