Solve x^2+1nx=x+1

$${ x }^{ 2 } +1nx = x+1$$

Solve for n

$$n=-x+1+\frac{1}{x}$$

$$x\neq 0$$

Steps for Solving Linear Equation

Subtract x^{2} from both sides.

$$1nx=x+1-x^{2}$$

Reorder the terms.

$$nx=-x^{2}+x+1$$

The equation is in standard form.

$$xn=1+x-x^{2}$$

Divide both sides by x.

$$\frac{xn}{x}=\frac{1+x-x^{2}}{x}$$

Dividing by x undoes the multiplication by x.

$$n=\frac{1+x-x^{2}}{x}$$

Divide -x^{2}+x+1 by x.

$$n=-x+1+\frac{1}{x}$$

Solve for x

$$x=\frac{\sqrt{n^{2}-2n+5}-n+1}{2}$$

$$x=\frac{-\sqrt{n^{2}-2n+5}-n+1}{2}$$