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a+b=19 ab=1\times 88=88
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+88. To find a and b, set up a system to be solved.
1,88 2,44 4,22 8,11
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 88.
1+88=89 2+44=46 4+22=26 8+11=19
Calculate the sum for each pair.
a=8 b=11
The solution is the pair that gives sum 19.
\left(x^{2}+8x\right)+\left(11x+88\right)
Rewrite x^{2}+19x+88 as \left(x^{2}+8x\right)+\left(11x+88\right).
x\left(x+8\right)+11\left(x+8\right)
Factor out x in the first and 11 in the second group.
\left(x+8\right)\left(x+11\right)
Factor out common term x+8 by using distributive property.
x^{2}+19x+88=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-19±\sqrt{19^{2}-4\times 88}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-19±\sqrt{361-4\times 88}}{2}
Square 19.
x=\frac{-19±\sqrt{361-352}}{2}
Multiply -4 times 88.
x=\frac{-19±\sqrt{9}}{2}
Add 361 to -352.
x=\frac{-19±3}{2}
Take the square root of 9.
x=-\frac{16}{2}
Now solve the equation x=\frac{-19±3}{2} when ± is plus. Add -19 to 3.
x=-8
Divide -16 by 2.
x=-\frac{22}{2}
Now solve the equation x=\frac{-19±3}{2} when ± is minus. Subtract 3 from -19.
x=-11
Divide -22 by 2.
x^{2}+19x+88=\left(x-\left(-8\right)\right)\left(x-\left(-11\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -8 for x_{1} and -11 for x_{2}.
x^{2}+19x+88=\left(x+8\right)\left(x+11\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.