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a+b=18 ab=1\times 32=32
Factor the expression by grouping. First, the expression needs to be rewritten as x^{2}+ax+bx+32. To find a and b, set up a system to be solved.
1,32 2,16 4,8
Since ab is positive, a and b have the same sign. Since a+b is positive, a and b are both positive. List all such integer pairs that give product 32.
1+32=33 2+16=18 4+8=12
Calculate the sum for each pair.
a=2 b=16
The solution is the pair that gives sum 18.
\left(x^{2}+2x\right)+\left(16x+32\right)
Rewrite x^{2}+18x+32 as \left(x^{2}+2x\right)+\left(16x+32\right).
x\left(x+2\right)+16\left(x+2\right)
Factor out x in the first and 16 in the second group.
\left(x+2\right)\left(x+16\right)
Factor out common term x+2 by using distributive property.
x^{2}+18x+32=0
Quadratic polynomial can be factored using the transformation ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right), where x_{1} and x_{2} are the solutions of the quadratic equation ax^{2}+bx+c=0.
x=\frac{-18±\sqrt{18^{2}-4\times 32}}{2}
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-18±\sqrt{324-4\times 32}}{2}
Square 18.
x=\frac{-18±\sqrt{324-128}}{2}
Multiply -4 times 32.
x=\frac{-18±\sqrt{196}}{2}
Add 324 to -128.
x=\frac{-18±14}{2}
Take the square root of 196.
x=-\frac{4}{2}
Now solve the equation x=\frac{-18±14}{2} when ± is plus. Add -18 to 14.
x=-2
Divide -4 by 2.
x=-\frac{32}{2}
Now solve the equation x=\frac{-18±14}{2} when ± is minus. Subtract 14 from -18.
x=-16
Divide -32 by 2.
x^{2}+18x+32=\left(x-\left(-2\right)\right)\left(x-\left(-16\right)\right)
Factor the original expression using ax^{2}+bx+c=a\left(x-x_{1}\right)\left(x-x_{2}\right). Substitute -2 for x_{1} and -16 for x_{2}.
x^{2}+18x+32=\left(x+2\right)\left(x+16\right)
Simplify all the expressions of the form p-\left(-q\right) to p+q.