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Solve for x (complex solution)
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x^{2}+18x+117=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-18±\sqrt{18^{2}-4\times 117}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 18 for b, and 117 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-18±\sqrt{324-4\times 117}}{2}
Square 18.
x=\frac{-18±\sqrt{324-468}}{2}
Multiply -4 times 117.
x=\frac{-18±\sqrt{-144}}{2}
Add 324 to -468.
x=\frac{-18±12i}{2}
Take the square root of -144.
x=\frac{-18+12i}{2}
Now solve the equation x=\frac{-18±12i}{2} when ± is plus. Add -18 to 12i.
x=-9+6i
Divide -18+12i by 2.
x=\frac{-18-12i}{2}
Now solve the equation x=\frac{-18±12i}{2} when ± is minus. Subtract 12i from -18.
x=-9-6i
Divide -18-12i by 2.
x=-9+6i x=-9-6i
The equation is now solved.
x^{2}+18x+117=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+18x+117-117=-117
Subtract 117 from both sides of the equation.
x^{2}+18x=-117
Subtracting 117 from itself leaves 0.
x^{2}+18x+9^{2}=-117+9^{2}
Divide 18, the coefficient of the x term, by 2 to get 9. Then add the square of 9 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+18x+81=-117+81
Square 9.
x^{2}+18x+81=-36
Add -117 to 81.
\left(x+9\right)^{2}=-36
Factor x^{2}+18x+81. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+9\right)^{2}}=\sqrt{-36}
Take the square root of both sides of the equation.
x+9=6i x+9=-6i
Simplify.
x=-9+6i x=-9-6i
Subtract 9 from both sides of the equation.