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x^{2}+146x+4704=0
All equations of the form ax^{2}+bx+c=0 can be solved using the quadratic formula: \frac{-b±\sqrt{b^{2}-4ac}}{2a}. The quadratic formula gives two solutions, one when ± is addition and one when it is subtraction.
x=\frac{-146±\sqrt{146^{2}-4\times 4704}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 146 for b, and 4704 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
x=\frac{-146±\sqrt{21316-4\times 4704}}{2}
Square 146.
x=\frac{-146±\sqrt{21316-18816}}{2}
Multiply -4 times 4704.
x=\frac{-146±\sqrt{2500}}{2}
Add 21316 to -18816.
x=\frac{-146±50}{2}
Take the square root of 2500.
x=-\frac{96}{2}
Now solve the equation x=\frac{-146±50}{2} when ± is plus. Add -146 to 50.
x=-48
Divide -96 by 2.
x=-\frac{196}{2}
Now solve the equation x=\frac{-146±50}{2} when ± is minus. Subtract 50 from -146.
x=-98
Divide -196 by 2.
x=-48 x=-98
The equation is now solved.
x^{2}+146x+4704=0
Quadratic equations such as this one can be solved by completing the square. In order to complete the square, the equation must first be in the form x^{2}+bx=c.
x^{2}+146x+4704-4704=-4704
Subtract 4704 from both sides of the equation.
x^{2}+146x=-4704
Subtracting 4704 from itself leaves 0.
x^{2}+146x+73^{2}=-4704+73^{2}
Divide 146, the coefficient of the x term, by 2 to get 73. Then add the square of 73 to both sides of the equation. This step makes the left hand side of the equation a perfect square.
x^{2}+146x+5329=-4704+5329
Square 73.
x^{2}+146x+5329=625
Add -4704 to 5329.
\left(x+73\right)^{2}=625
Factor x^{2}+146x+5329. In general, when x^{2}+bx+c is a perfect square, it can always be factored as \left(x+\frac{b}{2}\right)^{2}.
\sqrt{\left(x+73\right)^{2}}=\sqrt{625}
Take the square root of both sides of the equation.
x+73=25 x+73=-25
Simplify.
x=-48 x=-98
Subtract 73 from both sides of the equation.