Solve x^2+1=left(2-xright)^2

$${ x }^{ 2 } +1= { \left(2-x \right) }^{ 2 }$$

Solve for x

$$x=\frac{3}{4}=0.75$$

Steps for Solving Linear Equation

Use binomial theorem \left(a-b\right)^{2}=a^{2}-2ab+b^{2} to expand \left(2-x\right)^{2}.

$$x^{2}+1=4-4x+x^{2}$$

Add 4x to both sides.

$$x^{2}+1+4x=4+x^{2}$$

Subtract x^{2} from both sides.

$$x^{2}+1+4x-x^{2}=4$$

Combine x^{2} and -x^{2} to get 0.

$$1+4x=4$$

Subtract 1 from both sides.

$$4x=4-1$$

Subtract 1 from 4 to get 3.

$$4x=3$$

Divide both sides by 4.

$$x=\frac{3}{4}$$