Solve x^2+05x-075=0

$${ x }^{ 2 } +05x-075=0$$

Solve for x

$$x=0$$

Steps by Finding Square Root

Multiply 0 and 5 to get 0.

$$x^{2}+0x-0\times 75=0$$

Anything times zero gives zero.

$$x^{2}+0-0\times 75=0$$

Anything plus zero gives itself.

$$x^{2}-0\times 75=0$$

Multiply 0 and 75 to get 0.

$$x^{2}-0=0$$

Add 0 to both sides.

$$x^{2}=0+0$$

Add 0 and 0 to get 0.

$$x^{2}=0$$

Take the square root of both sides of the equation.

$$x=0 x=0$$

The equation is now solved. Solutions are the same.

$$x=0$$

Steps Using the Quadratic Formula

Multiply 0 and 5 to get 0.

$$x^{2}+0x-0\times 75=0$$

Anything times zero gives zero.

$$x^{2}+0-0\times 75=0$$

Anything plus zero gives itself.

$$x^{2}-0\times 75=0$$

Multiply 0 and 75 to get 0.

$$x^{2}-0=0$$

Reorder the terms.

$$x^{2}=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and 0 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$x=\frac{0±\sqrt{0^{2}}}{2}$$

Take the square root of 0^{2}.

$$x=\frac{0±0}{2}$$

Divide 0 by 2.

$$x=0$$