Solve x^2+6^2=left(x+2right)^2

$${ x }^{ 2 } + { 6 }^{ 2 } = { \left(x+2 \right) }^{ 2 }$$

Solve for x

$$x=8$$

Steps for Solving Linear Equation

Calculate 6 to the power of 2 and get 36.

$$x^{2}+36=\left(x+2\right)^{2}$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(x+2\right)^{2}.

$$x^{2}+36=x^{2}+4x+4$$

Subtract x^{2} from both sides.

$$x^{2}+36-x^{2}=4x+4$$

Combine x^{2} and -x^{2} to get 0.

$$36=4x+4$$

Swap sides so that all variable terms are on the left hand side.

$$4x+4=36$$

Subtract 4 from both sides.

$$4x=36-4$$

Subtract 4 from 36 to get 32.

$$4x=32$$

Divide both sides by 4.

$$x=\frac{32}{4}$$

Divide 32 by 4 to get 8.

$$x=8$$