Solve for x
x\in \left(-\infty,-2\sqrt{2}\right)\cup \left(2\sqrt{2},\infty\right)
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x^{2}>\left(2\sqrt{2}\right)^{2}
Calculate the square root of 8 and get 2\sqrt{2}. Rewrite 8 as \left(2\sqrt{2}\right)^{2}.
|x|>2\sqrt{2}
Inequality holds for |x|>2\sqrt{2}.
x<-2\sqrt{2}\text{; }x>2\sqrt{2}
Rewrite |x|>2\sqrt{2} as x<-2\sqrt{2}\text{; }x>2\sqrt{2}.
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