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\left(r-10\right)\left(r+10\right)=0
Consider r^{2}-100. Rewrite r^{2}-100 as r^{2}-10^{2}. The difference of squares can be factored using the rule: a^{2}-b^{2}=\left(a-b\right)\left(a+b\right).
r=10 r=-10
To find equation solutions, solve r-10=0 and r+10=0.
r^{2}=100
Add 100 to both sides. Anything plus zero gives itself.
r=10 r=-10
Take the square root of both sides of the equation.
r^{2}-100=0
Quadratic equations like this one, with an x^{2} term but no x term, can still be solved using the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}, once they are put in standard form: ax^{2}+bx+c=0.
r=\frac{0±\sqrt{0^{2}-4\left(-100\right)}}{2}
This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -100 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.
r=\frac{0±\sqrt{-4\left(-100\right)}}{2}
Square 0.
r=\frac{0±\sqrt{400}}{2}
Multiply -4 times -100.
r=\frac{0±20}{2}
Take the square root of 400.
r=10
Now solve the equation r=\frac{0±20}{2} when ± is plus. Divide 20 by 2.
r=-10
Now solve the equation r=\frac{0±20}{2} when ± is minus. Divide -20 by 2.
r=10 r=-10
The equation is now solved.