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\left(m^{2}-2n^{4}\right)\left(m^{4}+2m^{2}n^{4}+4n^{8}\right)
Rewrite m^{6}-8n^{12} as \left(m^{2}\right)^{3}-\left(2n^{4}\right)^{3}. The difference of cubes can be factored using the rule: a^{3}-b^{3}=\left(a-b\right)\left(a^{2}+ab+b^{2}\right).