Solve R^2=0.4286

$${ R }^{ 2 } = 0.4286$$

Solve for R

$$R=\frac{\sqrt{4286}}{100}\approx 0.654675492$$

$$R=-\frac{\sqrt{4286}}{100}\approx -0.654675492$$

Steps by Finding Square Root

Take the square root of both sides of the equation.

$$R=\frac{\sqrt{4286}}{100} R=-\frac{\sqrt{4286}}{100}$$

Steps Using the Quadratic Formula

Subtract 0.4286 from both sides.

$$R^{2}-0.4286=0$$

This equation is in standard form: ax^{2}+bx+c=0. Substitute 1 for a, 0 for b, and -0.4286 for c in the quadratic formula, \frac{-b±\sqrt{b^{2}-4ac}}{2a}.

$$R=\frac{0±\sqrt{0^{2}-4\left(-0.4286\right)}}{2}$$

Square 0.

$$R=\frac{0±\sqrt{-4\left(-0.4286\right)}}{2}$$

Multiply -4 times -0.4286.

$$R=\frac{0±\sqrt{1.7144}}{2}$$

Take the square root of 1.7144.

$$R=\frac{0±\frac{\sqrt{4286}}{50}}{2}$$

Now solve the equation R=\frac{0±\frac{\sqrt{4286}}{50}}{2} when ± is plus.

$$R=\frac{\sqrt{4286}}{100}$$

Now solve the equation R=\frac{0±\frac{\sqrt{4286}}{50}}{2} when ± is minus.

$$R=-\frac{\sqrt{4286}}{100}$$

The equation is now solved.

$$R=\frac{\sqrt{4286}}{100} R=-\frac{\sqrt{4286}}{100}$$