Solve K^=400left(6*306-74*14right)^2/80*320*20*380

$${ K }^{ } = \frac{ 400 { \left(6 \cdot 306-74 \cdot 14 \right) }^{ 2 } }{ 80 \cdot 320 \cdot 20 \cdot 380 }$$

Solve for K

$$K = \frac{25}{19} = 1\frac{6}{19} \approx 1.315789474$$

Steps for Solving Linear Equation

Calculate K to the power of 1 and get K.

$$K=\frac{400\left(6\times 306-74\times 14\right)^{2}}{80\times 320\times 20\times 380}$$

Cancel out 5\times 80 in both numerator and denominator.

$$K=\frac{\left(6\times 306-14\times 74\right)^{2}}{20\times 64\times 380}$$

Multiply 6 and 306 to get 1836.

$$K=\frac{\left(1836-14\times 74\right)^{2}}{20\times 64\times 380}$$

Multiply 14 and 74 to get 1036.

$$K=\frac{\left(1836-1036\right)^{2}}{20\times 64\times 380}$$

Subtract 1036 from 1836 to get 800.

$$K=\frac{800^{2}}{20\times 64\times 380}$$

Calculate 800 to the power of 2 and get 640000.

$$K=\frac{640000}{20\times 64\times 380}$$

Multiply 20 and 64 to get 1280.

$$K=\frac{640000}{1280\times 380}$$

Multiply 1280 and 380 to get 486400.

$$K=\frac{640000}{486400}$$

Reduce the fraction \frac{640000}{486400} to lowest terms by extracting and canceling out 25600.

$$K=\frac{25}{19}$$