Solve 8^2-4left(3^2+5right)+6*5-2^33^2

$${ 8 }^{ 2 } -4 \left( { 3 }^{ 2 } +5 \right) +6 \cdot 5- { 2 }^{ 3 } { 3 }^{ 2 }$$

Evaluate

$$-34$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$64-4\left(3^{2}+5\right)+6\times 5-2^{3}\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$64-4\left(9+5\right)+6\times 5-2^{3}\times 3^{2}$$

Add 9 and 5 to get 14.

$$64-4\times 14+6\times 5-2^{3}\times 3^{2}$$

Multiply 4 and 14 to get 56.

$$64-56+6\times 5-2^{3}\times 3^{2}$$

Subtract 56 from 64 to get 8.

$$8+6\times 5-2^{3}\times 3^{2}$$

Multiply 6 and 5 to get 30.

$$8+30-2^{3}\times 3^{2}$$

Add 8 and 30 to get 38.

$$38-2^{3}\times 3^{2}$$

Calculate 2 to the power of 3 and get 8.

$$38-8\times 3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$38-8\times 9$$

Multiply 8 and 9 to get 72.

$$38-72$$

Subtract 72 from 38 to get -34.

$$-34$$

Factor

$$-34$$