Solve 8^2-18x-5

$${ 8 }^{ 2 } -18x-5$$

Evaluate

$$59-18x$$

Solution Steps

Calculate 8 to the power of 2 and get 64.

$$64-18x-5$$

Subtract 5 from 64 to get 59.

$$59-18x$$

Differentiate w.r.t. x

$$-18$$

Steps Using Derivative Rule for Sum

Calculate 8 to the power of 2 and get 64.

$$\frac{\mathrm{d}}{\mathrm{d}x}(64-18x-5)$$

Subtract 5 from 64 to get 59.

$$\frac{\mathrm{d}}{\mathrm{d}x}(59-18x)$$

The derivative of a polynomial is the sum of the derivatives of its terms. The derivative of a constant term is 0. The derivative of ax^{n} is nax^{n-1}.

$$-18x^{1-1}$$

Subtract 1 from 1.

$$-18x^{0}$$

For any term t except 0, t^{0}=1.

$$-18$$