Solve 8^2+11^2-2*8*11cos(37^circ)

$${ 8 }^{ 2 } + { 11 }^{ 2 } -2 \cdot 8 \cdot 11 \cos ( 37 ^ { \circ } )$$

Evaluate

$$44.4401502316764672$$

Solution Steps

Evaluate trigonometric functions in the problem

$${(8)} ^ {2} + {(11)} ^ {2} - 2 \cdot 8 \cdot 11 \cdot 0.7986355100472928$$

Calculate 8 to the power of 2 and get 64.

$$64+11^{2}-2\times 8\times 11\times 0.7986355100472928$$

Calculate 11 to the power of 2 and get 121.

$$64+121-2\times 8\times 11\times 0.7986355100472928$$

Add 64 and 121 to get 185.

$$185-2\times 8\times 11\times 0.7986355100472928$$

Multiply 2 and 8 to get 16.

$$185-16\times 11\times 0.7986355100472928$$

Multiply 16 and 11 to get 176.

$$185-176\times 0.7986355100472928$$

Multiply 176 and 0.7986355100472928 to get 140.5598497683235328.

$$185-140.5598497683235328$$

Subtract 140.5598497683235328 from 185 to get 44.4401502316764672.

$$44.4401502316764672$$

Factor

$$\frac{3 \cdot 449 \cdot 644373930373}{2 ^ {7} \cdot 5 ^ {16}} = 44\frac{8596684212431}{19531250000000} = 44.44015023167647$$