Solve 7^2left(2-3+6right)-{64}^frac{1{3}}left(6+left(3+2left(4+2right)^2-1right)-1right)

$${ 7 }^{ 2 } \left( 2-3+6 \right) - { 64 }^{ \frac{ 1 }{ 3 } } \left( 6+ \left( 3+2 { \left(4+2 \right) }^{ 2 } -1 \right) -1 \right)$$

Evaluate

$$-71$$

Solution Steps

Calculate 7 to the power of 2 and get 49.

$$49\left(2-3+6\right)-64^{\frac{1}{3}}\left(6+3+2\left(4+2\right)^{2}-1-1\right)$$

Subtract 3 from 2 to get -1.

$$49\left(-1+6\right)-64^{\frac{1}{3}}\left(6+3+2\left(4+2\right)^{2}-1-1\right)$$

Add -1 and 6 to get 5.

$$49\times 5-64^{\frac{1}{3}}\left(6+3+2\left(4+2\right)^{2}-1-1\right)$$

Multiply 49 and 5 to get 245.

$$245-64^{\frac{1}{3}}\left(6+3+2\left(4+2\right)^{2}-1-1\right)$$

Calculate 64 to the power of \frac{1}{3} and get 4.

$$245-4\left(6+3+2\left(4+2\right)^{2}-1-1\right)$$

Add 6 and 3 to get 9.

$$245-4\left(9+2\left(4+2\right)^{2}-1-1\right)$$

Add 4 and 2 to get 6.

$$245-4\left(9+2\times 6^{2}-1-1\right)$$

Calculate 6 to the power of 2 and get 36.

$$245-4\left(9+2\times 36-1-1\right)$$

Multiply 2 and 36 to get 72.

$$245-4\left(9+72-1-1\right)$$

Add 9 and 72 to get 81.

$$245-4\left(81-1-1\right)$$

Subtract 1 from 81 to get 80.

$$245-4\left(80-1\right)$$

Subtract 1 from 80 to get 79.

$$245-4\times 79$$

Multiply 4 and 79 to get 316.

$$245-316$$

Subtract 316 from 245 to get -71.

$$-71$$

Factor

$$-71$$