Solve 7^=sqrt{3xe^2+xe^2}

$${ 7 }^{ } = \sqrt{ 3x { e }^{ 2 } +x { e }^{ 2 } }$$

Solve for x

$$x=\frac{49}{4e^{2}}\approx 1.65785722$$

Steps for Solving Radical Equations

Calculate 7 to the power of 1 and get 7.

$$7=\sqrt{3xe^{2}+xe^{2}}$$

Combine 3xe^{2} and xe^{2} to get 4xe^{2}.

$$7=\sqrt{4xe^{2}}$$

Swap sides so that all variable terms are on the left hand side.

$$\sqrt{4xe^{2}}=7$$

Square both sides of the equation.

$$4e^{2}x=49$$

Divide both sides by 4e^{2}.

$$\frac{4e^{2}x}{4e^{2}}=\frac{49}{4e^{2}}$$

Dividing by 4e^{2} undoes the multiplication by 4e^{2}.

$$x=\frac{49}{4e^{2}}$$