Solve 64^2+53^2+43^2+37^2+{29}^2+{23}^2

$${ 64 }^{ 2 } + { 53 }^{ 2 } + { 43 }^{ 2 } + { 37 }^{ 2 } + { 29 }^{ 2 } + { 23 }^{ 2 }$$

Evaluate

$$11493$$

Solution Steps

Calculate 64 to the power of 2 and get 4096.

$$4096+53^{2}+43^{2}+37^{2}+29^{2}+23^{2}$$

Calculate 53 to the power of 2 and get 2809.

$$4096+2809+43^{2}+37^{2}+29^{2}+23^{2}$$

Add 4096 and 2809 to get 6905.

$$6905+43^{2}+37^{2}+29^{2}+23^{2}$$

Calculate 43 to the power of 2 and get 1849.

$$6905+1849+37^{2}+29^{2}+23^{2}$$

Add 6905 and 1849 to get 8754.

$$8754+37^{2}+29^{2}+23^{2}$$

Calculate 37 to the power of 2 and get 1369.

$$8754+1369+29^{2}+23^{2}$$

Add 8754 and 1369 to get 10123.

$$10123+29^{2}+23^{2}$$

Calculate 29 to the power of 2 and get 841.

$$10123+841+23^{2}$$

Add 10123 and 841 to get 10964.

$$10964+23^{2}$$

Calculate 23 to the power of 2 and get 529.

$$10964+529$$

Add 10964 and 529 to get 11493.

$$11493$$

Factor

$$3^{2}\times 1277$$