Solve 5^5div5^3*5^-3

$${ 5 }^{ 5 } \div { 5 }^{ 3 } \cdot { 5 }^{ -3 }$$

Evaluate

$$\frac{1}{5}=0.2$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 3 from 5 to get 2.

$$5^{2}\times 5^{-3}$$

To multiply powers of the same base, add their exponents. Add 2 and -3 to get -1.

$$5^{-1}$$

Calculate 5 to the power of -1 and get \frac{1}{5}.

$$\frac{1}{5}$$

Factor

$$\frac{1}{5} = 0.2$$