Solve 4^x=29

$${ 4 }^{ x } =29$$

Solve for x

$$x = \frac{\log_{2} {(29)}}{2} \approx 2.428990498$$

Steps Using Definition of Logarithm

Use the rules of exponents and logarithms to solve the equation.

$$4^{x}=29$$

Take the logarithm of both sides of the equation.

$$\log(4^{x})=\log(29)$$

The logarithm of a number raised to a power is the power times the logarithm of the number.

$$x\log(4)=\log(29)$$

Divide both sides by \log(4).

$$x=\frac{\log(29)}{\log(4)}$$

By the change-of-base formula \frac{\log(a)}{\log(b)}=\log_{b}\left(a\right).

$$x=\log_{4}\left(29\right)$$

Solve for x (complex solution)

$$x=\frac{\pi n_{1}i}{\ln(2)}+\frac{\log_{2}\left(29\right)}{2}$$

$$n_{1}\in \mathrm{Z}$$