Solve 4^3-24^31^2=64^-2{64}^1^2

$${ 4 }^{ 3-2 } { 4 }^{ 3 { 1 }^{ 2 } } = { 64 }^{ -2 } { 64 }^{ { 1 }^{ 2 } }$$

Verify

Solution Steps

Subtract 2 from 3 to get 1.

$$4^{1}\times 4^{3\times 1^{2}}=64^{-2}\times 64^{1^{2}}$$

Calculate 4 to the power of 1 and get 4.

$$4\times 4^{3\times 1^{2}}=64^{-2}\times 64^{1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$4\times 4^{3\times 1}=64^{-2}\times 64^{1^{2}}$$

Multiply 3 and 1 to get 3.

$$4\times 4^{3}=64^{-2}\times 64^{1^{2}}$$

Calculate 4 to the power of 3 and get 64.

$$4\times 64=64^{-2}\times 64^{1^{2}}$$

Multiply 4 and 64 to get 256.

$$256=64^{-2}\times 64^{1^{2}}$$

Calculate 64 to the power of -2 and get \frac{1}{4096}.

$$256=\frac{1}{4096}\times 64^{1^{2}}$$

Calculate 1 to the power of 2 and get 1.

$$256=\frac{1}{4096}\times 64^{1}$$

Calculate 64 to the power of 1 and get 64.

$$256=\frac{1}{4096}\times 64$$

Multiply \frac{1}{4096} and 64 to get \frac{1}{64}.

$$256=\frac{1}{64}$$

Convert 256 to fraction \frac{16384}{64}.

$$\frac{16384}{64}=\frac{1}{64}$$

Compare \frac{16384}{64} and \frac{1}{64}.

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