Solve 4^2x+3^2x-7/5x*4^2

$${ 4 }^{ 2 } x+ { 3 }^{ 2 } x- \frac{ 7 }{ 5x \times { 4 }^{ 2 } }$$

Evaluate

$$25x-\frac{7}{80x}$$

Short Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16x+3^{2}x-\frac{7}{5x\times 4^{2}}$$

Calculate 3 to the power of 2 and get 9.

$$16x+9x-\frac{7}{5x\times 4^{2}}$$

Combine 16x and 9x to get 25x.

$$25x-\frac{7}{5x\times 4^{2}}$$

Calculate 4 to the power of 2 and get 16.

$$25x-\frac{7}{5x\times 16}$$

Multiply 5 and 16 to get 80.

$$25x-\frac{7}{80x}$$

To add or subtract expressions, expand them to make their denominators the same. Multiply 25x times \frac{80x}{80x}.

$$\frac{25x\times 80x}{80x}-\frac{7}{80x}$$

Since \frac{25x\times 80x}{80x} and \frac{7}{80x} have the same denominator, subtract them by subtracting their numerators.

$$\frac{25x\times 80x-7}{80x}$$

Do the multiplications in 25x\times 80x-7.

$$\frac{2000x^{2}-7}{80x}$$

Factor

$$\frac{2000x^{2}-7}{80x}$$