Solve 4^2-5*4^3+7*4^2-3*4+6

$${ 4 }^{ 2 } -5 \times { 4 }^{ 3 } +7 \times { 4 }^{ 2 } -3 \times 4+6$$

Evaluate

$$-198$$

Solution Steps

Calculate 4 to the power of 2 and get 16.

$$16-5\times 4^{3}+7\times 4^{2}-3\times 4+6$$

Calculate 4 to the power of 3 and get 64.

$$16-5\times 64+7\times 4^{2}-3\times 4+6$$

Multiply 5 and 64 to get 320.

$$16-320+7\times 4^{2}-3\times 4+6$$

Subtract 320 from 16 to get -304.

$$-304+7\times 4^{2}-3\times 4+6$$

Calculate 4 to the power of 2 and get 16.

$$-304+7\times 16-3\times 4+6$$

Multiply 7 and 16 to get 112.

$$-304+112-3\times 4+6$$

Add -304 and 112 to get -192.

$$-192-3\times 4+6$$

Multiply 3 and 4 to get 12.

$$-192-12+6$$

Subtract 12 from -192 to get -204.

$$-204+6$$

Add -204 and 6 to get -198.

$$-198$$

Factor

$$-198$$