Solve 4^2+8x/3=20+5x

$${ 4 }^{ 2 } + \frac{ 8x }{ 3 } =20+5x$$

Solve for x

$$x = -\frac{12}{7} = -1\frac{5}{7} \approx -1.714285714$$

Steps for Solving Linear Equation

Multiply both sides of the equation by 3.

$$3\times 4^{2}+8x=60+15x$$

Calculate 4 to the power of 2 and get 16.

$$3\times 16+8x=60+15x$$

Multiply 3 and 16 to get 48.

$$48+8x=60+15x$$

Subtract 15x from both sides.

$$48+8x-15x=60$$

Combine 8x and -15x to get -7x.

$$48-7x=60$$

Subtract 48 from both sides.

$$-7x=60-48$$

Subtract 48 from 60 to get 12.

$$-7x=12$$

Divide both sides by -7.

$$x=\frac{12}{-7}$$

Fraction \frac{12}{-7} can be rewritten as -\frac{12}{7} by extracting the negative sign.

$$x=-\frac{12}{7}$$