Solve 3^4-3*3^3+2*3^2-11*3+8=

$${ 3 }^{ 4 } -3 \times { 3 }^{ 3 } +2 \times { 3 }^{ 2 } -11 \times 3+8=$$

Evaluate

$$-7$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 3 to get 4.

$$3^{4}-3^{4}+2\times 3^{2}-11\times 3+8$$

Calculate 3 to the power of 4 and get 81.

$$81-3^{4}+2\times 3^{2}-11\times 3+8$$

Calculate 3 to the power of 4 and get 81.

$$81-81+2\times 3^{2}-11\times 3+8$$

Subtract 81 from 81 to get 0.

$$0+2\times 3^{2}-11\times 3+8$$

Calculate 3 to the power of 2 and get 9.

$$0+2\times 9-11\times 3+8$$

Multiply 2 and 9 to get 18.

$$0+18-11\times 3+8$$

Add 0 and 18 to get 18.

$$18-11\times 3+8$$

Multiply 11 and 3 to get 33.

$$18-33+8$$

Subtract 33 from 18 to get -15.

$$-15+8$$

Add -15 and 8 to get -7.

$$-7$$

Factor

$$-7$$