Solve 3^2-7*2-sqrt{49}+2-5^2

$${ 3 }^{ 2 } -7 \cdot 2- \sqrt{ 49 } +2- { 5 }^{ 2 }$$

Evaluate

$$-35$$

Solution Steps

Calculate 3 to the power of 2 and get 9.

$$9-7\times 2-\sqrt{49}+2-5^{2}$$

Multiply 7 and 2 to get 14.

$$9-14-\sqrt{49}+2-5^{2}$$

Subtract 14 from 9 to get -5.

$$-5-\sqrt{49}+2-5^{2}$$

Calculate the square root of 49 and get 7.

$$-5-7+2-5^{2}$$

Subtract 7 from -5 to get -12.

$$-12+2-5^{2}$$

Add -12 and 2 to get -10.

$$-10-5^{2}$$

Calculate 5 to the power of 2 and get 25.

$$-10-25$$

Subtract 25 from -10 to get -35.

$$-35$$

Factor

$$-35$$