Solve 3^2+x^2=left(1+xright)^2

$${ 3 }^{ 2 } + { x }^{ 2 } = { \left(1+x \right) }^{ 2 }$$

Solve for x

$$x=4$$

Steps for Solving Linear Equation

Calculate 3 to the power of 2 and get 9.

$$9+x^{2}=\left(1+x\right)^{2}$$

Use binomial theorem \left(a+b\right)^{2}=a^{2}+2ab+b^{2} to expand \left(1+x\right)^{2}.

$$9+x^{2}=1+2x+x^{2}$$

Subtract 2x from both sides.

$$9+x^{2}-2x=1+x^{2}$$

Subtract x^{2} from both sides.

$$9+x^{2}-2x-x^{2}=1$$

Combine x^{2} and -x^{2} to get 0.

$$9-2x=1$$

Subtract 9 from both sides.

$$-2x=1-9$$

Subtract 9 from 1 to get -8.

$$-2x=-8$$

Divide both sides by -2.

$$x=\frac{-8}{-2}$$

Divide -8 by -2 to get 4.

$$x=4$$