Solve 3^-4=1/3^=1/

$${ 3 }^{ -4 } = \frac{ 1 }{ { 3 }^{ } } = \frac{ 1 }{ }$$

Verify

Solution Steps

Divide 1 by 1 to get 1.

$$3^{-4}=\frac{1}{3^{1}}\text{ and }\frac{1}{3^{1}}=1$$

Calculate 3 to the power of -4 and get \frac{1}{81}.

$$\frac{1}{81}=\frac{1}{3^{1}}\text{ and }\frac{1}{3^{1}}=1$$

Calculate 3 to the power of 1 and get 3.

$$\frac{1}{81}=\frac{1}{3}\text{ and }\frac{1}{3^{1}}=1$$

Least common multiple of 81 and 3 is 81. Convert \frac{1}{81} and \frac{1}{3} to fractions with denominator 81.

$$\frac{1}{81}=\frac{27}{81}\text{ and }\frac{1}{3^{1}}=1$$

Compare \frac{1}{81} and \frac{27}{81}.

$$\text{false}\text{ and }\frac{1}{3^{1}}=1$$

Calculate 3 to the power of 1 and get 3.

$$\text{false}\text{ and }\frac{1}{3}=1$$

Convert 1 to fraction \frac{3}{3}.

$$\text{false}\text{ and }\frac{1}{3}=\frac{3}{3}$$

Compare \frac{1}{3} and \frac{3}{3}.

$$\text{false}\text{ and }\text{false}$$

The conjunction of \text{false} and \text{false} is \text{false}.

$$\text{false}$$