Solve 27^2+1/27

$${ 27 }^{ 2 } + \frac{ 1 }{ 27 }$$

Evaluate

$$\frac{19684}{27}\approx 729.037037037$$

Solution Steps

Calculate 27 to the power of 2 and get 729.

$$729+\frac{1}{27}$$

Convert 729 to fraction \frac{19683}{27}.

$$\frac{19683}{27}+\frac{1}{27}$$

Since \frac{19683}{27} and \frac{1}{27} have the same denominator, add them by adding their numerators.

$$\frac{19683+1}{27}$$

Add 19683 and 1 to get 19684.

$$\frac{19684}{27}$$

Factor

$$\frac{2 ^ {2} \cdot 7 \cdot 19 \cdot 37}{3 ^ {3}} = 729\frac{1}{27} = 729.0370370370371$$