Solve for a
a=-\frac{2^{x}-2}{3x}
x\neq 0
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a\times 3x-2=-2^{x}
Subtract 2^{x} from both sides. Anything subtracted from zero gives its negation.
a\times 3x=-2^{x}+2
Add 2 to both sides.
3xa=2-2^{x}
The equation is in standard form.
\frac{3xa}{3x}=\frac{2-2^{x}}{3x}
Divide both sides by 3x.
a=\frac{2-2^{x}}{3x}
Dividing by 3x undoes the multiplication by 3x.
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