Solve 2^5-3(3*7-2(6^2

$${ 2 }^{ 5 } -3(3 \times 7-2( { 6 }^{ 2 }$$

Evaluate

$$185$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$32-3\left(3\times 7-2\times 6^{2}\right)$$

Multiply 3 and 7 to get 21.

$$32-3\left(21-2\times 6^{2}\right)$$

Calculate 6 to the power of 2 and get 36.

$$32-3\left(21-2\times 36\right)$$

Multiply 2 and 36 to get 72.

$$32-3\left(21-72\right)$$

Subtract 72 from 21 to get -51.

$$32-3\left(-51\right)$$

Multiply 3 and -51 to get -153.

$$32-\left(-153\right)$$

The opposite of -153 is 153.

$$32+153$$

Add 32 and 153 to get 185.

$$185$$

Factor

$$5\times 37$$