Solve 2^5+5*2^4+10*2^3+10*2^2+5*2+1

$${ 2 }^{ 5 } +5 \times { 2 }^{ 4 } +10 \times { 2 }^{ 3 } +10 \times { 2 }^{ 2 } +5 \cdot 2+1$$

Evaluate

$$243$$

Solution Steps

Calculate 2 to the power of 5 and get 32.

$$32+5\times 2^{4}+10\times 2^{3}+10\times 2^{2}+5\times 2+1$$

Calculate 2 to the power of 4 and get 16.

$$32+5\times 16+10\times 2^{3}+10\times 2^{2}+5\times 2+1$$

Multiply 5 and 16 to get 80.

$$32+80+10\times 2^{3}+10\times 2^{2}+5\times 2+1$$

Add 32 and 80 to get 112.

$$112+10\times 2^{3}+10\times 2^{2}+5\times 2+1$$

Calculate 2 to the power of 3 and get 8.

$$112+10\times 8+10\times 2^{2}+5\times 2+1$$

Multiply 10 and 8 to get 80.

$$112+80+10\times 2^{2}+5\times 2+1$$

Add 112 and 80 to get 192.

$$192+10\times 2^{2}+5\times 2+1$$

Calculate 2 to the power of 2 and get 4.

$$192+10\times 4+5\times 2+1$$

Multiply 10 and 4 to get 40.

$$192+40+5\times 2+1$$

Add 192 and 40 to get 232.

$$232+5\times 2+1$$

Multiply 5 and 2 to get 10.

$$232+10+1$$

Add 232 and 10 to get 242.

$$242+1$$

Add 242 and 1 to get 243.

$$243$$

Factor

$$3^{5}$$