Solve 2^5+sqrt{49}div7-3^8/3^6

$${ 2 }^{ 5 } + \sqrt{ 49 } \div 7- \frac{ { 3 }^{ 8 } }{ { 3 }^{ 6 } }$$

Evaluate

$$24$$

Solution Steps

To divide powers of the same base, subtract the denominator's exponent from the numerator's exponent. Subtract 6 from 8 to get 2.

$$2^{5}+\frac{\sqrt{49}}{7}-3^{2}$$

Calculate 2 to the power of 5 and get 32.

$$32+\frac{\sqrt{49}}{7}-3^{2}$$

Calculate the square root of 49 and get 7.

$$32+\frac{7}{7}-3^{2}$$

Divide 7 by 7 to get 1.

$$32+1-3^{2}$$

Add 32 and 1 to get 33.

$$33-3^{2}$$

Calculate 3 to the power of 2 and get 9.

$$33-9$$

Subtract 9 from 33 to get 24.

$$24$$

Factor

$$2^{3}\times 3$$