Solve 2^4+32^3-2^2

$${ 2 }^{ 4 } +3 { 2 }^{ 3 } - { 2 }^{ 2 }$$

Evaluate

$$36$$

Solution Steps

Calculate 2 to the power of 4 and get 16.

$$16+3\times 2^{3}-2^{2}$$

Calculate 2 to the power of 3 and get 8.

$$16+3\times 8-2^{2}$$

Multiply 3 and 8 to get 24.

$$16+24-2^{2}$$

Add 16 and 24 to get 40.

$$40-2^{2}$$

Calculate 2 to the power of 2 and get 4.

$$40-4$$

Subtract 4 from 40 to get 36.

$$36$$

Factor

$$2^{2}\times 3^{2}$$