Solve 2^3+2*2^2-9*2-18

$${ 2 }^{ 3 } +2 \times { 2 }^{ 2 } -9 \times 2-18$$

Evaluate

$$-20$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2^{3}+2^{3}-9\times 2-18$$

Calculate 2 to the power of 3 and get 8.

$$8+2^{3}-9\times 2-18$$

Calculate 2 to the power of 3 and get 8.

$$8+8-9\times 2-18$$

Add 8 and 8 to get 16.

$$16-9\times 2-18$$

Multiply 9 and 2 to get 18.

$$16-18-18$$

Subtract 18 from 16 to get -2.

$$-2-18$$

Subtract 18 from -2 to get -20.

$$-20$$

Factor

$$-20$$