Solve 2^3+(-3^3)-2*(2^2)+4*2*(-3)+1

$${ 2 }^{ 3 } +(- { 3 }^{ 3 } )-2 \times ( { 2 }^{ 2 } )+4 \times 2 \times (-3)+1$$

Evaluate

$$-50$$

Solution Steps

To multiply powers of the same base, add their exponents. Add 1 and 2 to get 3.

$$2^{3}-3^{3}-2^{3}+4\times 2\left(-3\right)+1$$

Calculate 2 to the power of 3 and get 8.

$$8-3^{3}-2^{3}+4\times 2\left(-3\right)+1$$

Calculate 3 to the power of 3 and get 27.

$$8-27-2^{3}+4\times 2\left(-3\right)+1$$

Subtract 27 from 8 to get -19.

$$-19-2^{3}+4\times 2\left(-3\right)+1$$

Calculate 2 to the power of 3 and get 8.

$$-19-8+4\times 2\left(-3\right)+1$$

Subtract 8 from -19 to get -27.

$$-27+4\times 2\left(-3\right)+1$$

Multiply 4 and 2 to get 8.

$$-27+8\left(-3\right)+1$$

Multiply 8 and -3 to get -24.

$$-27-24+1$$

Subtract 24 from -27 to get -51.

$$-51+1$$

Add -51 and 1 to get -50.

$$-50$$

Factor

$$-50$$